(6w+3)(w+10)=0

Solution for (6w+3)(w+10)=0 equation:

(6w+3)(w+10)=0

We multiply parentheses ..

(+6w^2+60w+3w+30)=0

We get rid of parentheses

6w^2+60w+3w+30=0

We add all the numbers together, and all the variables

6w^2+63w+30=0

a = 6; b = 63; c = +30;
Δ = b2-4ac
Δ = 632-4·6·30
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3249}=57$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-57}{2*6}=\frac{-120}{12}
=-10
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+57}{2*6}=\frac{-6}{12}
=-1/2
$