(6w+5)(w-2)=0

Solution for (6w+5)(w-2)=0 equation:

(6w+5)(w-2)=0

We multiply parentheses ..

(+6w^2-12w+5w-10)=0

We get rid of parentheses

6w^2-12w+5w-10=0

We add all the numbers together, and all the variables

6w^2-7w-10=0

a = 6; b = -7; c = -10;
Δ = b2-4ac
Δ = -72-4·6·(-10)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-17}{2*6}=\frac{-10}{12}
=-5/6
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+17}{2*6}=\frac{24}{12}
=2
$