(6x)+4-2=10+(4x)-8

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Solution for (6x)+4-2=10+(4x)-8 equation: 



(6x)+4-2=10+(4x)-8

We move all terms to the left:

(6x)+4-2-(10+(4x)-8)=0

We add all the numbers together, and all the variables

6x-(4x+2)+4-2=0

We add all the numbers together, and all the variables

6x-(4x+2)+2=0

We get rid of parentheses

6x-4x-2+2=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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