(6x)/(3x-8)=8+(16)/(3x-8)

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Solution for (6x)/(3x-8)=8+(16)/(3x-8) equation: 



(6x)/(3x-8)=8+(16)/(3x-8)

We move all terms to the left:

(6x)/(3x-8)-(8+(16)/(3x-8))=0



Domain of the equation: (3x-8)!=0

We move all terms containing x to the left, all other terms to the right

3x!=8

x!=8/3

x!=2+2/3

x∈R





Domain of the equation: (3x-8))!=0

x∈R



We calculate fractions


(-30x^2)/((3x-8)*(3x-8)))+(-(16*(+3x))/((3x-8)*(3x-8)))=0



We calculate terms in parentheses: -(16*(+3x))/((3x-8)*(3x-8))), so:

16*(+3x))/((3x-8)*(3x-8))

We multiply all the terms by the denominator


16*(+3x))

We multiply parentheses

48x

Back to the equation:

-(48x)



We multiply all the terms by the denominator


(-30x^2)-48x*((3x-8)*(3x-8)))+(=0

We get rid of parentheses

-30x^2-48x*((3x-8)*(3x-8)))+(=0

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