(6x)2-5x=10

Solution for (6x)2-5x=10 equation:

(6x)2-5x=10

We move all terms to the left:

(6x)2-5x-(10)=0

We add all the numbers together, and all the variables

6x^2-5x-10=0

a = 6; b = -5; c = -10;
Δ = b2-4ac
Δ = -52-4·6·(-10)
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{265}}{2*6}=\frac{5-\sqrt{265}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{265}}{2*6}=\frac{5+\sqrt{265}}{12}
$