(6x+1)(3x+2)(x+2)=112

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Solution for (6x+1)(3x+2)(x+2)=112 equation: 



(6x+1)(3x+2)(x+2)=112

We move all terms to the left:

(6x+1)(3x+2)(x+2)-(112)=0

We multiply parentheses ..

(+18x^2+12x+3x+2)(x+2)-112=0

We move all terms containing x to the left, all other terms to the right

(+18x^2+12x+3x+2)(x+2)=112

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