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(6x+1)(3x+2)=(9x-1)(2x+5)-3x
We move all terms to the left:
(6x+1)(3x+2)-((9x-1)(2x+5)-3x)=0
We multiply parentheses ..
(+18x^2+12x+3x+2)-((9x-1)(2x+5)-3x)=0
We calculate terms in parentheses: -((9x-1)(2x+5)-3x), so:We get rid of parentheses
(9x-1)(2x+5)-3x
We add all the numbers together, and all the variables
-3x+(9x-1)(2x+5)
We multiply parentheses ..
(+18x^2+45x-2x-5)-3x
We get rid of parentheses
18x^2+45x-2x-3x-5
We add all the numbers together, and all the variables
18x^2+40x-5
Back to the equation:
-(18x^2+40x-5)
18x^2-18x^2+12x+3x-40x+2+5=0
We add all the numbers together, and all the variables
-25x+7=0
We move all terms containing x to the left, all other terms to the right
-25x=-7
x=-7/-25
x=7/25
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