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(6x+1)(x+7)=36
We move all terms to the left:
(6x+1)(x+7)-(36)=0
We multiply parentheses ..
(+6x^2+42x+x+7)-36=0
We get rid of parentheses
6x^2+42x+x+7-36=0
We add all the numbers together, and all the variables
6x^2+43x-29=0
a = 6; b = 43; c = -29;
Δ = b2-4ac
Δ = 432-4·6·(-29)
Δ = 2545
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-\sqrt{2545}}{2*6}=\frac{-43-\sqrt{2545}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+\sqrt{2545}}{2*6}=\frac{-43+\sqrt{2545}}{12} $
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