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(6x+1)(x-4)=196
We move all terms to the left:
(6x+1)(x-4)-(196)=0
We multiply parentheses ..
(+6x^2-24x+x-4)-196=0
We get rid of parentheses
6x^2-24x+x-4-196=0
We add all the numbers together, and all the variables
6x^2-23x-200=0
a = 6; b = -23; c = -200;
Δ = b2-4ac
Δ = -232-4·6·(-200)
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5329}=73$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-73}{2*6}=\frac{-50}{12} =-4+1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+73}{2*6}=\frac{96}{12} =8 $
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