(6x+1)+(9x-4)+108=180

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Solution for (6x+1)+(9x-4)+108=180 equation: 



(6x+1)+(9x-4)+108=180

We move all terms to the left:

(6x+1)+(9x-4)+108-(180)=0

We add all the numbers together, and all the variables

(6x+1)+(9x-4)-72=0

We get rid of parentheses

6x+9x+1-4-72=0

We add all the numbers together, and all the variables

15x-75=0

We move all terms containing x to the left, all other terms to the right

15x=75

x=75/15

x=5

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