(6x+1)/5=-10+(2x+1)/3

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Solution for (6x+1)/5=-10+(2x+1)/3 equation: 


x in (-oo:+oo)

(6*x+1)/5 = (2*x+1)/3-10 // - (2*x+1)/3-10

(6*x+1)/5-((2*x+1)/3)+10 = 0

(6*x+1)/5+(-1*(2*x+1))/3+10 = 0

(3*(6*x+1))/(3*5)+(-1*5*(2*x+1))/(3*5)+(3*5*10)/(3*5) = 0

3*(6*x+1)-1*5*(2*x+1)+3*5*10 = 0

8*x-2+150 = 0

8*x+148 = 0

(8*x+148)/(3*5) = 0

(8*x+148)/(3*5) = 0 // * 3*5

8*x+148 = 0

8*x+148 = 0 // - 148

8*x = -148 // : 8

x = -148/8

x = -37/2

x = -37/2

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