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(6x+1)5x+1=90
We move all terms to the left:
(6x+1)5x+1-(90)=0
We add all the numbers together, and all the variables
(6x+1)5x-89=0
We multiply parentheses
30x^2+5x-89=0
a = 30; b = 5; c = -89;
Δ = b2-4ac
Δ = 52-4·30·(-89)
Δ = 10705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{10705}}{2*30}=\frac{-5-\sqrt{10705}}{60} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{10705}}{2*30}=\frac{-5+\sqrt{10705}}{60} $
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