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(6x+10)4x=90
We move all terms to the left:
(6x+10)4x-(90)=0
We multiply parentheses
24x^2+40x-90=0
a = 24; b = 40; c = -90;
Δ = b2-4ac
Δ = 402-4·24·(-90)
Δ = 10240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10240}=\sqrt{1024*10}=\sqrt{1024}*\sqrt{10}=32\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-32\sqrt{10}}{2*24}=\frac{-40-32\sqrt{10}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+32\sqrt{10}}{2*24}=\frac{-40+32\sqrt{10}}{48} $
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