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(6x+12)(3x-12)=180
We move all terms to the left:
(6x+12)(3x-12)-(180)=0
We multiply parentheses ..
(+18x^2-72x+36x-144)-180=0
We get rid of parentheses
18x^2-72x+36x-144-180=0
We add all the numbers together, and all the variables
18x^2-36x-324=0
a = 18; b = -36; c = -324;
Δ = b2-4ac
Δ = -362-4·18·(-324)
Δ = 24624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24624}=\sqrt{1296*19}=\sqrt{1296}*\sqrt{19}=36\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36\sqrt{19}}{2*18}=\frac{36-36\sqrt{19}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36\sqrt{19}}{2*18}=\frac{36+36\sqrt{19}}{36} $
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