(6x+12)+(3x+2)=140

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Solution for (6x+12)+(3x+2)=140 equation: 



(6x+12)+(3x+2)=140

We move all terms to the left:

(6x+12)+(3x+2)-(140)=0

We get rid of parentheses

6x+3x+12+2-140=0

We add all the numbers together, and all the variables

9x-126=0

We move all terms containing x to the left, all other terms to the right

9x=126

x=126/9

x=14

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