(6x+12)-(3x-12)=78

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Solution for (6x+12)-(3x-12)=78 equation: 



(6x+12)-(3x-12)=78

We move all terms to the left:

(6x+12)-(3x-12)-(78)=0

We get rid of parentheses

6x-3x+12+12-78=0

We add all the numbers together, and all the variables

3x-54=0

We move all terms containing x to the left, all other terms to the right

3x=54

x=54/3

x=18

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