(6x+18)=(9x+12)

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Solution for (6x+18)=(9x+12) equation: 



(6x+18)=(9x+12)

We move all terms to the left:

(6x+18)-((9x+12))=0

We get rid of parentheses

6x-((9x+12))+18=0



We calculate terms in parentheses: -((9x+12)), so:

(9x+12)

We get rid of parentheses

9x+12

Back to the equation:

-(9x+12)



We get rid of parentheses

6x-9x-12+18=0

We add all the numbers together, and all the variables

-3x+6=0

We move all terms containing x to the left, all other terms to the right

-3x=-6

x=-6/-3

x=+2

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