(6x+2)(-6x+0)=2(6x+2)

Solution for (6x+2)(-6x+0)=2(6x+2) equation:

(6x+2)(-6x+0)=2(6x+2)

We move all terms to the left:

(6x+2)(-6x+0)-(2(6x+2))=0

We add all the numbers together, and all the variables

(6x+2)(-6x)-(2(6x+2))=0

We multiply parentheses ..

(-36x^2-12x)-(2(6x+2))=0


We calculate terms in parentheses: -(2(6x+2)), so:

2(6x+2)

We multiply parentheses

12x+4

Back to the equation:

-(12x+4)


We get rid of parentheses

-36x^2-12x-12x-4=0

We add all the numbers together, and all the variables

-36x^2-24x-4=0

a = -36; b = -24; c = -4;
Δ = b2-4ac
Δ = -242-4·(-36)·(-4)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{24}{-72}=-1/3$