(6x+2)(2x+10)=0

Solution for (6x+2)(2x+10)=0 equation:

(6x+2)(2x+10)=0

We multiply parentheses ..

(+12x^2+60x+4x+20)=0

We get rid of parentheses

12x^2+60x+4x+20=0

We add all the numbers together, and all the variables

12x^2+64x+20=0

a = 12; b = 64; c = +20;
Δ = b2-4ac
Δ = 642-4·12·20
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-56}{2*12}=\frac{-120}{24}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+56}{2*12}=\frac{-8}{24}
=-1/3
$