(6x+20)+4x+(80-2x)=180

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Solution for (6x+20)+4x+(80-2x)=180 equation: 



(6x+20)+4x+(80-2x)=180

We move all terms to the left:

(6x+20)+4x+(80-2x)-(180)=0

We add all the numbers together, and all the variables

(6x+20)+4x+(-2x+80)-180=0

We add all the numbers together, and all the variables

4x+(6x+20)+(-2x+80)-180=0

We get rid of parentheses

4x+6x-2x+20+80-180=0

We add all the numbers together, and all the variables

8x-80=0

We move all terms containing x to the left, all other terms to the right

8x=80

x=80/8

x=10

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