(6x+21)+(3x+19)=2x+96

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Solution for (6x+21)+(3x+19)=2x+96 equation: 



(6x+21)+(3x+19)=2x+96

We move all terms to the left:

(6x+21)+(3x+19)-(2x+96)=0

We get rid of parentheses

6x+3x-2x+21+19-96=0

We add all the numbers together, and all the variables

7x-56=0

We move all terms containing x to the left, all other terms to the right

7x=56

x=56/7

x=8

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