(6x+22)=(64-x)

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Solution for (6x+22)=(64-x) equation: 



(6x+22)=(64-x)

We move all terms to the left:

(6x+22)-((64-x))=0

We add all the numbers together, and all the variables

(6x+22)-((-1x+64))=0

We get rid of parentheses

6x-((-1x+64))+22=0



We calculate terms in parentheses: -((-1x+64)), so:

(-1x+64)

We get rid of parentheses

-1x+64

Back to the equation:

-(-1x+64)



We get rid of parentheses

6x+1x-64+22=0

We add all the numbers together, and all the variables

7x-42=0

We move all terms containing x to the left, all other terms to the right

7x=42

x=42/7

x=6

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