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(6x+26)(16x)=180
We move all terms to the left:
(6x+26)(16x)-(180)=0
We multiply parentheses
96x^2+416x-180=0
a = 96; b = 416; c = -180;
Δ = b2-4ac
Δ = 4162-4·96·(-180)
Δ = 242176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{242176}=\sqrt{256*946}=\sqrt{256}*\sqrt{946}=16\sqrt{946}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(416)-16\sqrt{946}}{2*96}=\frac{-416-16\sqrt{946}}{192} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(416)+16\sqrt{946}}{2*96}=\frac{-416+16\sqrt{946}}{192} $
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