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(6x+3)(2x+4)=0
We multiply parentheses ..
(+12x^2+24x+6x+12)=0
We get rid of parentheses
12x^2+24x+6x+12=0
We add all the numbers together, and all the variables
12x^2+30x+12=0
a = 12; b = 30; c = +12;
Δ = b2-4ac
Δ = 302-4·12·12
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-18}{2*12}=\frac{-48}{24} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+18}{2*12}=\frac{-12}{24} =-1/2 $
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