(6x+3)+(9x+44)=77

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Solution for (6x+3)+(9x+44)=77 equation:



(6x+3)+(9x+44)=77
We move all terms to the left:
(6x+3)+(9x+44)-(77)=0
We get rid of parentheses
6x+9x+3+44-77=0
We add all the numbers together, and all the variables
15x-30=0
We move all terms containing x to the left, all other terms to the right
15x=30
x=30/15
x=2

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