(6x+3)/11=10-(3x-1)/2

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Solution for (6x+3)/11=10-(3x-1)/2 equation: 



(6x+3)/11=10-(3x-1)/2

We move all terms to the left:

(6x+3)/11-(10-(3x-1)/2)=0

We calculate fractions


6x/()+(-(10-(3x-1)*11)/()=0



We calculate terms in parentheses: +(-(10-(3x-1)*11)/(), so:

-(10-(3x-1)*11)/(

We multiply all the terms by the denominator


-(10-(3x-1)*11)



We calculate terms in parentheses: -(10-(3x-1)*11), so:

10-(3x-1)*11

determiningTheFunctionDomain
-(3x-1)*11+10

We multiply parentheses

-33x+11+10

We add all the numbers together, and all the variables

-33x+21

Back to the equation:

-(-33x+21)



We get rid of parentheses

33x-21

Back to the equation:

+(33x-21)



We get rid of parentheses

6x/()+33x-21=0

We multiply all the terms by the denominator


6x+33x*()-21*()=0

We add all the numbers together, and all the variables

6x+33x*()=0

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