(6x+3)2=13x-18

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Solution for (6x+3)2=13x-18 equation: 



(6x+3)2=13x-18

We move all terms to the left:

(6x+3)2-(13x-18)=0

We multiply parentheses

12x-(13x-18)+6=0

We get rid of parentheses

12x-13x+18+6=0

We add all the numbers together, and all the variables

-1x+24=0

We move all terms containing x to the left, all other terms to the right

-x=-24

x=-24/-1

x=+24

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