(6x+32)+(4x)+38=180

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Solution for (6x+32)+(4x)+38=180 equation: 



(6x+32)+(4x)+38=180

We move all terms to the left:

(6x+32)+(4x)+38-(180)=0

We add all the numbers together, and all the variables

4x+(6x+32)-142=0

We get rid of parentheses

4x+6x+32-142=0

We add all the numbers together, and all the variables

10x-110=0

We move all terms containing x to the left, all other terms to the right

10x=110

x=110/10

x=11

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