(6x+4)(2x-1)-(8x+3)(2x+5)+(4x+3)(x-1)=5

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Solution for (6x+4)(2x-1)-(8x+3)(2x+5)+(4x+3)(x-1)=5 equation:



(6x+4)(2x-1)-(8x+3)(2x+5)+(4x+3)(x-1)=5
We move all terms to the left:
(6x+4)(2x-1)-(8x+3)(2x+5)+(4x+3)(x-1)-(5)=0
We multiply parentheses ..
(+12x^2-6x+8x-4)-(8x+3)(2x+5)+(4x+3)(x-1)-5=0
We get rid of parentheses
12x^2-6x+8x-(8x+3)(2x+5)+(4x+3)(x-1)-4-5=0
We multiply parentheses ..
12x^2-(+16x^2+40x+6x+15)-6x+8x+(4x+3)(x-1)-4-5=0
We add all the numbers together, and all the variables
12x^2-(+16x^2+40x+6x+15)+2x+(4x+3)(x-1)-9=0
We get rid of parentheses
12x^2-16x^2-40x-6x+2x+(4x+3)(x-1)-15-9=0
We multiply parentheses ..
12x^2-16x^2+(+4x^2-4x+3x-3)-40x-6x+2x-15-9=0
We add all the numbers together, and all the variables
-4x^2+(+4x^2-4x+3x-3)-44x-24=0
We get rid of parentheses
-4x^2+4x^2-4x+3x-44x-3-24=0
We add all the numbers together, and all the variables
-45x-27=0
We move all terms containing x to the left, all other terms to the right
-45x=27
x=27/-45
x=-3/5

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