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(6x+4)(2x-1)=0
We multiply parentheses ..
(+12x^2-6x+8x-4)=0
We get rid of parentheses
12x^2-6x+8x-4=0
We add all the numbers together, and all the variables
12x^2+2x-4=0
a = 12; b = 2; c = -4;
Δ = b2-4ac
Δ = 22-4·12·(-4)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-14}{2*12}=\frac{-16}{24} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+14}{2*12}=\frac{12}{24} =1/2 $
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