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(6x+4)(5x+2)=0
We multiply parentheses ..
(+30x^2+12x+20x+8)=0
We get rid of parentheses
30x^2+12x+20x+8=0
We add all the numbers together, and all the variables
30x^2+32x+8=0
a = 30; b = 32; c = +8;
Δ = b2-4ac
Δ = 322-4·30·8
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-8}{2*30}=\frac{-40}{60} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+8}{2*30}=\frac{-24}{60} =-2/5 $
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