(6x+4)-6+2x=3(4x+3)+1

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Solution for (6x+4)-6+2x=3(4x+3)+1 equation: 



(6x+4)-6+2x=3(4x+3)+1

We move all terms to the left:

(6x+4)-6+2x-(3(4x+3)+1)=0

We add all the numbers together, and all the variables

2x+(6x+4)-(3(4x+3)+1)-6=0

We get rid of parentheses

2x+6x-(3(4x+3)+1)+4-6=0



We calculate terms in parentheses: -(3(4x+3)+1), so:

3(4x+3)+1

We multiply parentheses

12x+9+1

We add all the numbers together, and all the variables

12x+10

Back to the equation:

-(12x+10)



We add all the numbers together, and all the variables

8x-(12x+10)-2=0

We get rid of parentheses

8x-12x-10-2=0

We add all the numbers together, and all the variables

-4x-12=0

We move all terms containing x to the left, all other terms to the right

-4x=12

x=12/-4

x=-3

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