(6x+4)/8=(-3x+12)/3

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Solution for (6x+4)/8=(-3x+12)/3 equation: 



(6x+4)/8=(-3x+12)/3

We move all terms to the left:

(6x+4)/8-((-3x+12)/3)=0

We calculate fractions


6x/()+(-((-3x+12)*8)/()=0



We calculate terms in parentheses: +(-((-3x+12)*8)/(), so:

-((-3x+12)*8)/(

We multiply all the terms by the denominator


-((-3x+12)*8)



We calculate terms in parentheses: -((-3x+12)*8), so:

(-3x+12)*8

We multiply parentheses

-24x+96

Back to the equation:

-(-24x+96)



We get rid of parentheses

24x-96

Back to the equation:

+(24x-96)



We get rid of parentheses

6x/()+24x-96=0

We multiply all the terms by the denominator


6x+24x*()-96*()=0

We add all the numbers together, and all the variables

6x+24x*()=0

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