(6x+48+4x+32)/4=75

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Solution for (6x+48+4x+32)/4=75 equation:



(6x+48+4x+32)/4=75
We move all terms to the left:
(6x+48+4x+32)/4-(75)=0
We add all the numbers together, and all the variables
(10x+80)/4-75=0
We multiply all the terms by the denominator
(10x+80)-75*4=0
We add all the numbers together, and all the variables
(10x+80)-300=0
We get rid of parentheses
10x+80-300=0
We add all the numbers together, and all the variables
10x-220=0
We move all terms containing x to the left, all other terms to the right
10x=220
x=220/10
x=22

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