(6x+5)(3-4x)=-8x(3x-7)

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Solution for (6x+5)(3-4x)=-8x(3x-7) equation: 



(6x+5)(3-4x)=-8x(3x-7)

We move all terms to the left:

(6x+5)(3-4x)-(-8x(3x-7))=0

We add all the numbers together, and all the variables

(6x+5)(-4x+3)-(-8x(3x-7))=0

We multiply parentheses ..

(-24x^2+18x-20x+15)-(-8x(3x-7))=0



We calculate terms in parentheses: -(-8x(3x-7)), so:

-8x(3x-7)

We multiply parentheses

-24x^2+56x

Back to the equation:

-(-24x^2+56x)



We get rid of parentheses

-24x^2+24x^2+18x-20x-56x+15=0

We add all the numbers together, and all the variables

-58x+15=0

We move all terms containing x to the left, all other terms to the right

-58x=-15

x=-15/-58

x=15/58

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