(6x+5)(7x-4)=79

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Solution for (6x+5)(7x-4)=79 equation:



(6x+5)(7x-4)=79
We move all terms to the left:
(6x+5)(7x-4)-(79)=0
We multiply parentheses ..
(+42x^2-24x+35x-20)-79=0
We get rid of parentheses
42x^2-24x+35x-20-79=0
We add all the numbers together, and all the variables
42x^2+11x-99=0
a = 42; b = 11; c = -99;
Δ = b2-4ac
Δ = 112-4·42·(-99)
Δ = 16753
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{16753}}{2*42}=\frac{-11-\sqrt{16753}}{84} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{16753}}{2*42}=\frac{-11+\sqrt{16753}}{84} $

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