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(6x+5)(9x+8)=0
We multiply parentheses ..
(+54x^2+48x+45x+40)=0
We get rid of parentheses
54x^2+48x+45x+40=0
We add all the numbers together, and all the variables
54x^2+93x+40=0
a = 54; b = 93; c = +40;
Δ = b2-4ac
Δ = 932-4·54·40
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(93)-3}{2*54}=\frac{-96}{108} =-8/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(93)+3}{2*54}=\frac{-90}{108} =-5/6 $
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