(6x+5)+(4x-2)=93

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Solution for (6x+5)+(4x-2)=93 equation: 



(6x+5)+(4x-2)=93

We move all terms to the left:

(6x+5)+(4x-2)-(93)=0

We get rid of parentheses

6x+4x+5-2-93=0

We add all the numbers together, and all the variables

10x-90=0

We move all terms containing x to the left, all other terms to the right

10x=90

x=90/10

x=9

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