(6x+5)/(2x-7)=(21x-4)/(7x+7)

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Solution for (6x+5)/(2x-7)=(21x-4)/(7x+7) equation:


D( x )

2*x-7 = 0

7*x+7 = 0

2*x-7 = 0

2*x-7 = 0

2*x-7 = 0 // + 7

2*x = 7 // : 2

x = 7/2

7*x+7 = 0

7*x+7 = 0

7*x+7 = 0 // - 7

7*x = -7 // : 7

x = -7/7

x = -1

x in (-oo:-1) U (-1:7/2) U (7/2:+oo)

(6*x+5)/(2*x-7) = (21*x-4)/(7*x+7) // - (21*x-4)/(7*x+7)

(6*x+5)/(2*x-7)-((21*x-4)/(7*x+7)) = 0

(6*x+5)/(2*x-7)+(-1*(21*x-4))/(7*x+7) = 0

((6*x+5)*(7*x+7))/((2*x-7)*(7*x+7))+(-1*(21*x-4)*(2*x-7))/((2*x-7)*(7*x+7)) = 0

(6*x+5)*(7*x+7)-1*(21*x-4)*(2*x-7) = 0

232*x+7 = 0

(232*x+7)/((2*x-7)*(7*x+7)) = 0

(232*x+7)/((2*x-7)*(7*x+7)) = 0 // * (2*x-7)*(7*x+7)

232*x+7 = 0

232*x+7 = 0 // - 7

232*x = -7 // : 232

x = -7/232

x = -7/232

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