(6x+54)+3x-28)=125

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Solution for (6x+54)+3x-28)=125 equation: 



(6x+54)+3x-28)=125

We move all terms to the left:

(6x+54)+3x-28)-(125)=0

We add all the numbers together, and all the variables

3x+(6x+54)=0

We get rid of parentheses

3x+6x+54=0

We add all the numbers together, and all the variables

9x+54=0

We move all terms containing x to the left, all other terms to the right

9x=-54

x=-54/9

x=-6

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