(6x+7)(2x-3)=(4x+5)(3x+2)

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Solution for (6x+7)(2x-3)=(4x+5)(3x+2) equation: 



(6x+7)(2x-3)=(4x+5)(3x+2)

We move all terms to the left:

(6x+7)(2x-3)-((4x+5)(3x+2))=0

We multiply parentheses ..

(+12x^2-18x+14x-21)-((4x+5)(3x+2))=0



We calculate terms in parentheses: -((4x+5)(3x+2)), so:

(4x+5)(3x+2)

We multiply parentheses ..

(+12x^2+8x+15x+10)

We get rid of parentheses

12x^2+8x+15x+10

We add all the numbers together, and all the variables

12x^2+23x+10

Back to the equation:

-(12x^2+23x+10)



We get rid of parentheses

12x^2-12x^2-18x+14x-23x-21-10=0

We add all the numbers together, and all the variables

-27x-31=0

We move all terms containing x to the left, all other terms to the right

-27x=31

x=31/-27

x=-1+4/27

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