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(6x+7)(5x-8)=0
We multiply parentheses ..
(+30x^2-48x+35x-56)=0
We get rid of parentheses
30x^2-48x+35x-56=0
We add all the numbers together, and all the variables
30x^2-13x-56=0
a = 30; b = -13; c = -56;
Δ = b2-4ac
Δ = -132-4·30·(-56)
Δ = 6889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6889}=83$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-83}{2*30}=\frac{-70}{60} =-1+1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+83}{2*30}=\frac{96}{60} =1+3/5 $
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