(6x+7)(x+1)=0

Solution for (6x+7)(x+1)=0 equation:

(6x+7)(x+1)=0

We multiply parentheses ..

(+6x^2+6x+7x+7)=0

We get rid of parentheses

6x^2+6x+7x+7=0

We add all the numbers together, and all the variables

6x^2+13x+7=0

a = 6; b = 13; c = +7;
Δ = b2-4ac
Δ = 132-4·6·7
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-1}{2*6}=\frac{-14}{12}
=-1+1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+1}{2*6}=\frac{-12}{12}
=-1
$