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(6x+7)(x-7)=0
We multiply parentheses ..
(+6x^2-42x+7x-49)=0
We get rid of parentheses
6x^2-42x+7x-49=0
We add all the numbers together, and all the variables
6x^2-35x-49=0
a = 6; b = -35; c = -49;
Δ = b2-4ac
Δ = -352-4·6·(-49)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-49}{2*6}=\frac{-14}{12} =-1+1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+49}{2*6}=\frac{84}{12} =7 $
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