(6x+7)/3=(9x+3)/7

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Solution for (6x+7)/3=(9x+3)/7 equation: 



(6x+7)/3=(9x+3)/7

We move all terms to the left:

(6x+7)/3-((9x+3)/7)=0

We calculate fractions


6x/()+(-((9x+3)*3)/()=0



We calculate terms in parentheses: +(-((9x+3)*3)/(), so:

-((9x+3)*3)/(

We multiply all the terms by the denominator


-((9x+3)*3)



We calculate terms in parentheses: -((9x+3)*3), so:

(9x+3)*3

We multiply parentheses

27x+9

Back to the equation:

-(27x+9)



We get rid of parentheses

-27x-9

Back to the equation:

+(-27x-9)



We get rid of parentheses

6x/()-27x-9=0

We multiply all the terms by the denominator


6x-27x*()-9*()=0

We add all the numbers together, and all the variables

6x-27x*()=0

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