(6x+72)=(2x+28)

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Solution for (6x+72)=(2x+28) equation: 



(6x+72)=(2x+28)

We move all terms to the left:

(6x+72)-((2x+28))=0

We get rid of parentheses

6x-((2x+28))+72=0



We calculate terms in parentheses: -((2x+28)), so:

(2x+28)

We get rid of parentheses

2x+28

Back to the equation:

-(2x+28)



We get rid of parentheses

6x-2x-28+72=0

We add all the numbers together, and all the variables

4x+44=0

We move all terms containing x to the left, all other terms to the right

4x=-44

x=-44/4

x=-11

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