(6x+9)+(10x-27)+((6x+9)+(10x-27)-180)=180

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Solution for (6x+9)+(10x-27)+((6x+9)+(10x-27)-180)=180 equation: 



(6x+9)+(10x-27)+((6x+9)+(10x-27)-180)=180

We move all terms to the left:

(6x+9)+(10x-27)+((6x+9)+(10x-27)-180)-(180)=0

We get rid of parentheses

6x+10x+((6x+9)+(10x-27)-180)+9-27-180=0



We calculate terms in parentheses: +((6x+9)+(10x-27)-180), so:

(6x+9)+(10x-27)-180

We get rid of parentheses

6x+10x+9-27-180

We add all the numbers together, and all the variables

16x-198

Back to the equation:

+(16x-198)



We add all the numbers together, and all the variables

16x+(16x-198)-198=0

We get rid of parentheses

16x+16x-198-198=0

We add all the numbers together, and all the variables

32x-396=0

We move all terms containing x to the left, all other terms to the right

32x=396

x=396/32

x=12+3/8

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