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(6x-1)(3x+6)=0
We multiply parentheses ..
(+18x^2+36x-3x-6)=0
We get rid of parentheses
18x^2+36x-3x-6=0
We add all the numbers together, and all the variables
18x^2+33x-6=0
a = 18; b = 33; c = -6;
Δ = b2-4ac
Δ = 332-4·18·(-6)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-39}{2*18}=\frac{-72}{36} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+39}{2*18}=\frac{6}{36} =1/6 $
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