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(6x-1)(9x+3)=0
We multiply parentheses ..
(+54x^2+18x-9x-3)=0
We get rid of parentheses
54x^2+18x-9x-3=0
We add all the numbers together, and all the variables
54x^2+9x-3=0
a = 54; b = 9; c = -3;
Δ = b2-4ac
Δ = 92-4·54·(-3)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-27}{2*54}=\frac{-36}{108} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+27}{2*54}=\frac{18}{108} =1/6 $
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