(6x-1)(x+2)=(3x+4)(2x+5)

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Solution for (6x-1)(x+2)=(3x+4)(2x+5) equation: 



(6x-1)(x+2)=(3x+4)(2x+5)

We move all terms to the left:

(6x-1)(x+2)-((3x+4)(2x+5))=0

We multiply parentheses ..

(+6x^2+12x-1x-2)-((3x+4)(2x+5))=0



We calculate terms in parentheses: -((3x+4)(2x+5)), so:

(3x+4)(2x+5)

We multiply parentheses ..

(+6x^2+15x+8x+20)

We get rid of parentheses

6x^2+15x+8x+20

We add all the numbers together, and all the variables

6x^2+23x+20

Back to the equation:

-(6x^2+23x+20)



We get rid of parentheses

6x^2-6x^2+12x-1x-23x-2-20=0

We add all the numbers together, and all the variables

-12x-22=0

We move all terms containing x to the left, all other terms to the right

-12x=22

x=22/-12

x=-1+5/6

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